If $\frac{I_1}{I_2} = \frac{16}{1},$ then $\frac{I_{\max}}{I_{\min}} = ?$

Explain the pattern of diffraction produced by two slits by drawing a figure.

In the Young's double slit experiment using a monochromatic light of wavelength $\lambda$,the path difference (in terms of an integer $n$) corresponding to any point having half the peak intensity is:

In Young's double slit experiment, the wavelength of light used is $\lambda$. The intensity on the screen at a point for path difference $\lambda/6$ is $X$. The intensity at the point for path difference $\lambda/3$ is (Given: $\cos 180^{\circ} = -1, \cos 30^{\circ} = \frac{\sqrt{3}}{2}$)

In Young's double-slit experiment,the intensity at a point where the path difference is $\lambda / 6$ is $I'$. If $I_0$ denotes the maximum intensity,then $I'/I_0$ is equal to

Waves emitted from two identical sources produce an intensity of $K$ units at a point on the screen. If the path difference between these two waves is $\lambda$,calculate the intensity at a point on the screen where the path difference is $\lambda/4$.